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Russell Wilson named NFC Offensive Player of the Week after clutch performance vs. Eagles

Philadelphia Eagles v Seattle Seahawks Photo by Jonathan Ferrey/Getty Images

Russell Wilson led the Seattle Seahawks to a vital 24-10 win over the favored Philadelphia Eagles on Sunday Night Football, as #3 threw three touchdown passes and frustrated one of the best defenses in the league on his way to one of his best performances on the year.

Wilson’s final numbers were 20/31 for 227 yards, 31 rushing yards, plus the aforementioned three touchdowns to go along with a turnover-free game against a defense that had managed ten takeaways in its four previous outings. His reward? Another NFC Offensive Player of the Week award.

This is the second time this season that Wilson has taken NFC Offensive Player of the Week honors, and I have a feeling you know the other game. If you don’t, then Houston, we have a problem.

Wilson has now won seven Player of the Week awards, tied with Shaun Alexander for the most in Seahawks history. Russell’s first one came on December 2nd, 2012, when he heroically led Seattle to an overtime road win over the Chicago Bears, and kicked off an unforgettable late-season burst of offense en route to a playoff berth that would not have happened had they lost.

The other Player of the Week performances from Wilson came against New Orleans in December 2013, at Washington in October 2014, at Arizona in December 2014, vs. Pittsburgh in November 2015, and then the two he’s picked up this season. If you’re keeping track, four of his seven POTW awards occurred in December games.

Unlike other POTW performances, this one has national media talking about Russell Wilson as a serious MVP candidate for the first time in his career.